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Prove that sin 2 A is equal to 2 sinAcosA. Oct 18, 2019 ... Sin4A+sin2A divide by 1+cos2A+cos4A= tan2A prove it · Expert-Verified Answer · Answer · New questions in Math. Construct a triangle with sides 5 ... May 21, 2020 ... If sinA=(3/5) and A is in first quadrant, then the values of sin2A, cos2A and tan2A are (A) 24/25, 7/25, 24/7 (B) 1/25, 7/25, 1/7 (C) 24/25, ... Comparing with the given expression, we get ⇒ a = 1, b = 3, c = 3 ⇒ a + b + c = 1 + 3 + 3 = 7 Therefore, the required value of a + b + c is 7. Jul 24, 2020 ... If sin A = 3/5 than find the sin 2A, sin A = \frac{3}{5}, cos A = \sqrt{1- (\frac{3}{5})^2, cos A = \frac{4}{5}, sin 2A Dec 29, 2021 ... Simplify sin2θ1+cosθ+sin2θ1−cosθ. View Solution · Prove that 1+sin2Acos2A=cosA+sinAcosA−sinA. View Solution · Prove that :1+sin2Acos2A=cosA+sinA ... Apr 22, 2021 ... 1-cos2A/sin2A ={(sin^2A + cos^2A)–(cos^2A – sin^2A)}/2sinA.cosA = 2sin^2A/2sinA.cosA = tanA = RHS sin A + sin 2 A = x ⇒ x 2 = [ sin A + sin 2 A ] 2 ⇒ x 2 = sin 2 A + sin 2 2 A + 2 sin A . sin 2 A y = cos A + cos 2 A May 7, 2020 ... Step-by-step explanation: 2 sin square( 45°-A) (therefore; by trigonometry ratios sin45°=1) =2sin2(1-A) =2sin(1-A) =1+sin2A hence proved. Nov 18, 2008 ... I proved the right side, which eventually lead up to cosA - sinA / cosA + sinA. I have NO idea how to do the left side.