Nếu sin x = 0, hãy đơn giản biểu thức (sin x + sin 3x) / cos x.

C-x (sinx-Cos x=0. Page 2. 2. -. Let f be the function with derivative given by f'(x) = x² - a² = (x − a) (x + a), where a is a positive constant. Which of the ... (u'-σ) cos(x) - (u+o') sin(x) y" ty = u· cos(x) - V'. sin(x) u'.sin(x) +σ'• cos(x)=0 u' • cos(x) -σ' .sin(x) = "COS (X). Multiply 1st eqh by sin(x), and by cos( ... May 4, 2021 ... sinx/(cosx+1) = -(cosx-1)/sinx multiply by sinx sin^2x/(cosx+1) = -(cosx-1) multiply by cosx+1 sin^2x = -(cos^2x-1) = 0 cos 'x sin 'x. 0 sin 'x cos 'x. 2. 6. 4. 3. 7. 5. Е2:2:3:26Ж. Uy И cos 'y. 0 sin 'y. 0. 1. 0 sin 'y. 0 cos 'y. 2. 6. 4. 3. 7. 5. Sep 18, 2022 ... Solutions are , , , So when 0 < x < 360°, x has 4 solutions. ∴ The correct option is (4). Download Soln PDF Apr 9, 2015 ... which shows, taking x to 0, that the limit of x/sinx must be 1. The difficult bit is now to show that the limit of sinh−hh2 is actually zero. Jun 3, 2021 ... Share your videos with friends, family, and the world. Aug 5, 2022 ... Sin is the y coordinate of the intersection of the angle theta with the circle, and cosine is the x coordinate. So intrinsically to the circle, this equation ... [0,π]. f′(x) = − sin x − 2 sin x cos x f′(x)=0=⇒ − sin x − 2 sin x cos x =0=⇒ − sin x(1 + 2 cos) = 0. =⇒ sin x =0=⇒ x = 0, π. or. =⇒ 1 + 2 cos x =0=⇒ cos x = −. Sep 5, 2019 ... sin x = 0, x = nπ ; cos x = 0, x = (nπ + π/2) ; tan x = 0, x = nπ ; sin x = 1, x = (2nπ + π/2) = (4n+1)π/2 ; cos x = 1, x = 2nπ.