= 0 trong khoảng [-2π, 2π].

= sinx + sinx · 1 = 2 sinx. Now, f2(x) = sinx + R π/2. 0 sinxcosy · f1( ... Jun 3, 2021 ... Share your videos with friends, family, and the world. sin(x) him sin h30 d. -sin(x). Similarly [sin(x)] = cos(x) dx. Find equation of tangent line to y=sin(x) at x=0 slope y-41. X-X,. X d [sin(x)], dx y-sin(o). X. ... (x) ≈ f(0) + f0(0)x + f00(0). 2 x2. (x ≈ 0) f(x) f0(x) f00(x) f(0) f0(0) f00(0) sin x cos x. − sin x. 0. 1. 0 cos x. − sin x. − cos x. 1. 0. −1 ex ex. 3x. 1. 1. ... x=∫10∫y0ey2dxdy. With this ... ∫5π/2π/2∫1sinxf(x,y)dydx. Hence f is not differentiable at x = 0. 7[20P]) Show that sin(x) < x for all x > 0. Solution: This is clearly correct for x > 1 as sin x ≤ 1. Set F(x) = x − sin ... g(x) = x2 − 3 if x ≤ 0, sin(x) if x > 0. Prove that g is discontinuous at 0. Answer: Let ε = 2 and let δ > 0 be given. Choose x ∈ ( ... u(0,t)=0, u(2,t)=0 u(x,0) = 3 sin(2πx). Take the Laplace transform and apply the initial condition. d2U dx2. (x, s) = sU(x, s) ... We still need to evaluate it between x = 0 and x = π. 2 . Since sin(0) = 0 = sin(π) and −cos(π) = 1 = cos(0), we have the final answer: Zπ/2. 0 x. 2 sin(2x)dx =. y f x. = is shown above. (a) Write the first four nonzero terms of the Taylor series for sin x about. 0, x = and write the first four nonzero terms.