Ứng dụng trong khoa học chính trị và thống kê xã hội.

Jun 2, 2020 ... x^2 + y^2 = 4(x + y).= x^2 -4x + y^2-4y = 0. (x-2)^2 + ( y-2)^2 = 8 this is a circle with center at 2,2 and r = sqrt 8 max will be 2 + sqrt ... Using the following equation, x 2 + 2x + y 2 + 4y = 20 we get the centre as (-1, -2) and radius r as 5. May 30, 2016 ... Put the equation into standard form to find it to be a circle with radius 3 and center (−1,2). Explanation: In order to put the equation of a conic section ... over the compact region. −1 ≤ x ≤ 1, 0 ≤ y ≤ 2. Solution: We look for the critical points in the interior: ∇f = (2x − 2+2y,4y − 2+ ... Let second-degree equation be, ax 2 + by 2 + 2hxy + 2gx + 2fy + c = 0. Discriminant = Δ = Case: 1 If discriminant (Δ) of this equation doesn't Dec 3, 2021 ... x^2+y^2 +2x - 4y - 8 = 0 Here are 2 methods: 1️⃣ Compare quadratic x²+y²+2fx+2gy+c = 0 & centre (-f,-g) 2f = 2 ⟹ f =1 also 2g = -4 ⟹ g = -2 so ... B) 4y(3x − 5y)(3x + 5y). C) 4y(3x − 5y)(3x − 5y). D) 4y(9x ... Given x = 2 and y = −3, evaluate the expression given below. 2x2 ... Bestimmen Sie das Volumen des RotationskSrpers, der durch Rotation des durch den Funktionsgraphen von y = x/x 2-16 (x e [ 4; 8 ]) und der. Dec 18, 2017 ... 1)²(x² y=2x+1)(2+2)² + (x+1)" (3\6°²+2x] (2x+2). (b) (4 points) y = (2x+1)√2x+1 y= 2. (2x+1)2 + (2x+1) (te) (2x+1)12 (2). (c) (4 points) y =. ... ( x,y) ® ( 2,3), xy. 2. lim ( x,y) ® ( 3,4), (x2+y2). 3. lim ( x,y) ® ( 2,p), xcos(y). 4. lim ( x,y) ® ( p,2), sin( xy). 5. lim ( x,y) ® ( 2,1), x2y2-x2-4y2+4. yx ...