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over the compact region. −1 ≤ x ≤ 1, 0 ≤ y ≤ 2. Solution: We look for the critical points in the interior: ∇f = (2x − 2+2y,4y − 2+ ... x2,−4y2−2x+16y−40=0 reprsents · The correct Answer is:C · x2−16=0,y2−9y+20=0 · Two circles x2+y2−2x−4y=0 and x2+y2−8y−4=0 · I. x2+4x+4=0. II. y2−8y+16=0. Dec 7, 2023 ... ... 2]. In particular, one may refer [3, 19] for finding integer. points on the some specific three dimensional surface. This. communication co ... Dec 3, 2023 ... The foci of the graph represented byx^2-4y^2+2x+8y-7 = 0 is #nimcet2023 Downloads our APP for FREE Study Material ,Video Class ,Test paper ... May 30, 2016 ... Put the equation into standard form to find it to be a circle with radius 3 and center (−1,2). Explanation: In order to put the equation of a conic section ... y. (2x+5y+3) = 5 and x. (5x 4y+2) = 5, so sin e these are equal, the ODE is exa t. The integral will have the form F(x; y) = R. 2x + 5y + 3dx = x2 + 5xy + 3x + ... (xA+yB)·C = (x+5y, x+2y,−x−4y)·(2,2,3) = 2x+ 10y +2x+4y −3x−12y = x+2y. Therefore (xA + yB) · C = 0 if and only if x = −2y. This means that the vectors xA + ... 4 9 XY X 4 Y 9 49315 9 49 2 Z4 2 Z[ \4 4 1 9 ]1 Z19 Z4 5 4 54 9 5 31 4 31 2 Z ^1 5 2219 5 Y 5 31 19 Y Z42 45Y 9 994 1 9 Z45 Z4 Z ^1 [ Z454 4 1^24Y 54 49 2 9919 ... = ∆4y(0) = 24 andso b4 = 1. 6b3. = ∆3y(0) = 36 andso ... y = x(4) + 6x(3) + 4x(2) - 2x + 6. = x(x - 1)(x - 2)(x - 3) + 6x(x - 1)(x - 2) + 4x(x - 1) - 2x + 6. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, ...
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