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Jul 17, 2019 ... prove sinA+cosA/(sinA-cosA) + sinA-cosA/(sinA+cosA)=1/(sin2A-cos2A)=2/(1-2cos2A)=2sec2A/(tan2A-1). Dhanalakshmi July 17, 2019, 5:46am 2. = cosA cosB − sinA sinB cos(A − B) = cosA cosB + sinA sinB sin2 A + cos2 A = 1, sin 2A = 2 sinA cosA cos 2A = 2 cos2 A ... sina:H-cos^ _ sinx — ? ' C. ' h. Dé?-* 2. 2. A . _. „ sina?— cosa: 2. 2 sinar + cosa: 2 sina; — cosa? _. _ sina: — cosa: — Cxex. Ce* cosa: H. 2 sina:-4-cosa; ^ ... Jan 8, 2022 ... Have an idea on how to solve the most popular question from trigonometry. If you feel it easy do not forget to share the links of the ... Solve for a variable, factor, expand, evaluate fractions, linear equations, quadratic equations, inequalities, systems of equations, matrices. - cos²α cos & + cosa sina sin) cosx sina cos✪ + sin² α sin cosa ( cosa cos € + sina ( cos x cos cos α cos (α Ө sina cos (x cos (α-8) (cos α). (b) The ... Dec 17, 2020 ... Calculation: (sinA + cosA)/(sinA – cosA) = 5/4 ⇒ 4(sin A + cos A) = 5(sin A – cos A) ⇒ 4sinA + 4cosA = 5sinA – 5cosA ⇒ Feb 11, 2021 ... sin A cos A(cos 2 A + sin 2 A) = sin A cos A (1) ........[∵ sin 2 θ + cos 2 θ = 1] = sin A cos A = उजवी बाजू ∴ tan A ( 1 + tan 2 4 v33 sina cosa sino g². Page 3. Prob 2. 10 pers (r²dijnr). © Iij = fav puсs (r² dij after the rotation r₁ = Tij rj. I'j = for p'ei's (ri² dij - kйrэs. 2. +4. Sep 10, 2016 ... (secA-cosecA)(sec^2+cosec^2A+secAcosecA)={(1+cosA/sinA+sinA/cosA) (sinA-cosA)}/(1/cosA -1/sinA)(1/cos^2A
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