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Jul 23, 2014 ... Chapter : Trigonometric Ratios Upto Transformations Lesson : Trigonometric Ratios Of Multiple & Sub-Multiple Angles For More Information ... Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA Sep 10, 2016 ... (secA-cosecA)(sec^2+cosec^2A+secAcosecA)={(1+cosA/sinA+sinA/cosA) (sinA-cosA)}/(1/cosA -1/sinA)(1/cos^2A Sep 16, 2002 ... sina. sinA. = sinb. sinB. = sinc. sinC. Cosine Rule sides. Cosine Rule angles cosa = cosbcosc+sinbsinccosA cosb= cosccosa+sincsinacosB cosc ... Prove that: (cosA - sinA + 1) / (cosA + sinA +1) = (1 - sinA) / cosA. Answer: For solving this questions we need to rationalize the denominator. cosa. 2 cosa.... sina.. l. l 5. 2Ï3 sina . (3).. c... 2. 2 cosa.. Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12 How can I solve sinA-cosA=1 where 0 degree<=A<=90 degree. Thank you. Nazrul,. One way to approach this problem is to use sin2A = 1 - cos2A and hence write. = sinB cosC + sinC cosB + sinC cosA + sinAcosC. + sinAcosB + sinB cosA. = sinA(cosB + cosC) + sinB(cosC + cosA). + sinC(cosA + cosB). (9). Since 0 < sinA ≤ 1 ... The three main trigonometric functions, sine (sin), cosine (cos), and tangent (tan), each define a ratio of two side lengths with respect to an angle of a ...