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How can I solve sinA-cosA=1 where 0 degree<=A<=90 degree. Thank you. Nazrul,. One way to approach this problem is to use sin2A = 1 - cos2A and hence write. Feb 11, 2021 ... sin A cos A(cos 2 A + sin 2 A) = sin A cos A (1) ........[∵ sin 2 θ + cos 2 θ = 1] = sin A cos A = उजवी बाजू ∴ tan A ( 1 + tan 2 Request PDF | On Jan 1, 2019, Kathleen Slane and others published Cosa ... Sina. However, translated from Greek by Huneyn b. Ishak, Salaman and Absal ... = cosA cosB − sinA sinB cos(A − B) = cosA cosB + sinA sinB sin2 A + cos2 A = 1, sin 2A = 2 sinA cosA cos 2A = 2 cos2 A ... Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA Jul 23, 2018 ... The value of Sin A + Cos A actually depends on the variable 'a' so we can not actually prodict out the exact answer to this question. sina:H-cos^ _ sinx — ? ' C. ' h. Dé?-* 2. 2. A . _. „ sina?— cosa: 2. 2 sinar + cosa: 2 sina; — cosa? _. _ sina: — cosa: — Cxex. Ce* cosa: H. 2 sina:-4-cosa; ^ ... Jul 17, 2019 ... prove sinA+cosA/(sinA-cosA) + sinA-cosA/(sinA+cosA)=1/(sin2A-cos2A)=2/(1-2cos2A)=2sec2A/(tan2A-1). Dhanalakshmi July 17, 2019, 5:46am 2. May 21, 2018 ... 2 Answers ... Dean R. ... It seemed easier to start from the right; please see proof below. Explanation: We need the crudest cosine double angle ... Oct 31, 2022 ... How do you prove SinA+cosA-1/SinA-cosA+1= 1-sinA/cosA? Submission accepted by. Abu Khan. · See parent question. Answer.