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May 13, 2015 ... The problem is: lim x->0 of (tan7x)/(sin3x) I know that lim x->0 (sinx)/x = 1, but I don't really know how to apply that here. Feb 5, 2015 ... 5 Answers 5 ... The computation can be done simply as follows tan2xsin3x=sin2xsin3xcos2x=2sinxcosx[sinx(2cos2x+1)]cos2x=2cosx(2cos2x+1)cos2x→2⋅1(2 ... 3x dx. ∫. ;. (d) cos(3x)sin(3x)dx. ∫ . 5. Evaluate the integral. 0 exp(2sin )cos x x dx π. ∫ . 6. Evaluate cos(2 ) x x dx. Sep 9, 2014 ... In this problem, y = c1 cos 3x + c2 sin 3x is a two parameter family of solutions of the second-order DE y?? + 9y = 0. Oct 29, 2020 ... Rewrite the sum as a product. sin(3x) + sin(7x) · sin(3x) + sin(7x)= sin(7x)+sin(3x) · sin(3x) + sin(7x). 1+ sin 3x. SECTION 102. 0

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