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The function has a discontinuity at x = 0 because it is not defined at x = 0. ... 1 Based on the graph, why do you think y = tan(x) is said to have an infinite ... This is the same as x < tan x. (b) Show that x/ sin x is a strictly increasing function on (0, π/2). Solution: If ... x1=x0-f(x0)f′(x0) ... 4. sin(x), sin(x). 5. cos(x), cos(x). 6. tan(x), tan(x). 7. sec(x), sec(x). 8. cosec(x), csc(x). 9. cot(x), cot(x). 10. sin- ... ∫ln(cosx)tan(x)dx d. ∫. 1. √9−x2 dx e. ∫xcos(x)dx. 3 ... Max: x=0; Min: x=4 c. Up: (−2,−1) ∪ (1,2) ∪ (3,5); Down: (−1,1) ∪ (2,3) ... tan-1 (tan2 x) , 2 sin2 x. They discovered this on a graph plotting calculator. The graphs appear below. Notice that they cross at x = 0, 7/4, I/2, 37r/4 ... ... tangent is π. y = tan x. A graph of y = cot x is given in figure 3. Notice there are asymptotes for angles where cotangent is undefined, such as x = 0 and x = π ... tan x − (3x2 − 5x).(tan x)′. (tan x)2. = (6x − 5). tan x − (3x2 ... (c) f is not differentialble at x = 0,x = 4 . Page 4. Page 5. 9. x2y = 13, 500 ... Tangent Function: f(x) = tan x. Domain: All real numbers except π/2 + k, where k is an integer. Range: All real numbers. X-Intercept: (kπ, 0) where k is an ... -x4 < x4 cos (==) = X", X+0 0 lim. X-0. -X. 4 lim. X-0. X. 2. 10. Therefore lim xco ... (tan x) (2x+ex) + (x² + e * ) (sec² x). (x² + sinx) (ex + sinx) - (ex ... ... x^6 exp(x), y(1) = 0. See the steps for using Laplace transforms to solve ... y''(x) + tan(x) y'(x) + sec(x)^2 y(x)==0 · x^4*y*y'' + x^4*y'*y' + 3*x^3*y*y ...
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