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1 = √ sec² u du = tanu +. C. = } x3 tan x³ + C. 40. For I = ⇒ f csc² x (cotx-1)3 dx, let u = cotx - 1 du= -csc² x dx. Then. I=- Sử du=-tu^ +C =-d (cotx − 1)+C. ... cot(x)=tan(x)1​= ... 1+cos(2x)1−cos(2x)​. sin2(x) = ½[1 − cos( ... Apr 3, 2016 ... It depends on your perspective. It is true that, in elementary mathematics, the two functions aren't the same because of domain issues. Jan 23, 2019 ... Answer: 1 Step-by-step explanation: 1. Convert the denominator to cos terms. 2. Further add the terms in the denominator. 3. Take SinxCosx ( or Sin theta cos ... Nov 21, 2024 ... ... 1[chi](r)rm with finite cotangent power sums. Special emphasis is given to the quadratic character [chi](n) = (n/p), p an odd prime. A new ... ... cot(x+c). The value of |a| is called the amplitude and c is the phase angle ... setBorder(0); initPicture(-5,5.01) axes(1, 1, "labels", "grid") stroke ... ... (1) = 7g(1) + g0(1) = 38. 42. f0(x) = -6e−2xg(x)+3e−2xg0(x), so f0(0) = -6g ... csc x dx = - ln | csc x + cot x| + C. 58. Z x sin(3x) dx = -. 1. 3 x cos ... ... 1)Bm+1[2(m+ 1)]!·cotxx=1x2m∑j=122(m−j+1)[22(m−j ... If x = pi/2, then csc(x) = 1 and cot(x) = 0; 1 + 0 = 1 if x = 3pi/2, then csc(x) = -1 and cot(x) = 0 Jul 16, 2015 ... tan x + cot x = sinx/cosx + cosx/sinx = [get a common denominator] [sin^2x + cos^2x] / [sinx*cosx] = 1/ [sin x * cosx