Viết một chương trình máy tính để tìm nghiệm của phương trình cos3x-sin2x=0. Tìm điều kiện của tham số để phương trình cos3x-sin2x=m có nghiệm.

Apr 4, 2025 ... Explanation: Given cot2x. cot3x = 1 ⇒ cos2x. cos3x – sin2x.sin3x= 0 ⇒ cos(2x+3x) = cos5x = 0 0 < x < π. We use the initial condition to evaluate the constants. We compute y/ = 3C1 cos 3x - 3c2 sin 3x + 2. 5 cos 2x. Use y(0) = ... ... cos 3x + B2x2 sin 3x) + A3 cos 2x + B3 sin 2x. C. yp(x) = ex(A1 cos 3x ... + y = sin x, y(0) = 0,y. /. (0) = 1. Find the value of y(π. 2. ). A. π. 4. B. 3π. C ... Apr 3, 2015 ... Where n=0,1,2,…….] 2x=2nπ+(π/2)-3x or 2x=nπ-((π/2)-3x). Therefore, general solution ... Apr 7, 2021 ... Answers (1) · Deependra Verma · Similar Questions · Latest Question. I want advance city information slip for NEET 2025 · At the bottom of a ... Feb 12, 2024 ... The question is as Follows:- Sin(2x) + Cos(3x) = 0, 0. ... Doom_Clown. • 1y ago. Sin2x + Cos3x=0. Sin2x + sin(π/2 - 3x) =0. Oct 17, 2020 ... ... sin ⁡ ( x ) =≠ 0 {\displaystyle W={\begin{bmatrix}\cos(x)&\sin(3x)\\-\sin(x)&3\cos(3x)\end{bmatrix}}=3\cos(x)\cos(3x)+\sin(3x)\sin(x)=\neq 0\!}. Apr 3, 2013 ... This problem can be solved in a much simpler way. sin(-2x) = cos(3x) => cos(pi/2 + 2x) = cos(3x) pi/2 + 2x = 3x => x = 0.5pi or Ic = [sinxln(sin3x + cos3x)]π/2. 0. − 3∫ π/2. 0 sinx(sin2x cosx − cos2x sinx) sin3x + cos3x dx. = −3∫ π/2. 0 sin3x cosx − cos2x(1 − cos2x) sin3x + cos3x dx. = − ... u = 1, and, v = sin (x). du/dx = 0, and, dv/dx = cos (x). Inserting this into the quotient rule yields: dy/dx, = sin (x) × 0 − 1 × cos (x)/sin2(x). = −cos (x)/ ...