Tìm nghiệm của phương trình sin^2 x + sin^2 2x + sin^2 3x = 2.

Hence f is not differentiable at x = 0. 7[20P]) Show that sin(x) < x for all x > 0. Solution: This is clearly correct for x > 1 as sin x ≤ 1. Set F(x) = x − sin ... ... functions is key. Ex lim x² sin l'/x. X70. Proot -1≤ sin (1/x) =) for all x*0. ૧. -x^< x'sin l'/x) Ex° for all Xsc. But lim - x²= lim lim x ² = 0. X70. X70. Sin ... At what value of x in the interval 0 ≤x≤π do the graphs of ƒ and g have parallel tangent lines? (A) 0. (B) 0.660. (C) 2.083. (D) ... The period of the sin(x) sin ( x ) function is 2π 2 π so values will repeat every 2π 2 π radians in both directions. Since x0 was arbitrarily chosen hence the function f(x) is continuous in R. Each fk(x) = sin(x/k) k is differentiable with. Solution. Let f(x) = x − 1 − sin x. Then f(0) = −1 < 0 and f(π/2) ... g(x) = x2 − 3 if x ≤ 0, sin(x) if x > 0. Prove that g is discontinuous at 0. Answer: Let ε = 2 and let δ > 0 be given. Choose x ∈ ( ... ... x − [cos (sin x)] sin x f′′(0) = 0;. (4.78) f′′′(x) = {[−sin (sin x)] cos2x}′ − {[cos (sin x)] sin x}′. = −cos (sin x) cos3x + 2 sin (sin x) cosx sin x. +sin ... – (f + g)(x)=4+ x2 for x ≥ 0; = x2 for x < 0;. – (fg)(x)=4x2 for x ≥ 0; = 0 for x < 0; ... (e) Since sinx and cosx are continuous, their ratio tanx = sin x. Sep 11, 2018 ... The area under the curve y = | cos x - sin x |, 0 le x le (π/2), and above x-axis is: (A) 2 √2 (B) 2 √2 - 2 (C) 2 √2 + 2 (D) 0.