Xét tính hội tụ của chuỗi Fourier của hàm số f(x) = sin2x + cosx.

Nov 25, 2016 ... Explanation: ... Using the identity from above, rewrite the equation. ... Now factor out a cosx . ... Now take each factor and set it equal to zero. (x2 − 3x + 3) ≥ 0, x + 2 x + 3. > 2x + 3 x + 6 . 2. Draw a graph of the ... sin 2x = sinx, 2 sinx + cosx = 1, log(x2 + 1) = 2 log(3 − x). 4. Express ... A student solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. What was the student's error? Please give the correct answer. 1 - cosx is continuous everywhere and has zeros where 1 - cos x x = 2n ... cos x + sin 2x = − sin 2x + sin 2x = 0. Using Theorem 3, we see that ƒ (x) ... sin2x = cosx. 1 – cos2x = cosx. M1 Rearrange, and use sin2x = 1 – cos2x. (or equiv with cot2x or cosec2x) cos2x + cosx – 1 = 0. A1 Obtain correct quadratic in ... satisfied for sinx = 0, or for cosx = 1. 2 . In our range, this occurs when x = π, or x = π. 3 . Using the second derivative test, we see that f′′(π) > 0, and f ... Find the general solution : sin2x+cosx=0 · The correct Answer is:x=(2n+1)π2 or x=nπ+(−1)n7π6,n∈Z · sin2x+cosx=0 2sinxcosx+cosx=0 cosx(2sinx+1)=0 cosx=0 or sinx= ... 2sin(x)cos(x) = sin(2x). Jtan(x) dx = ln I ~_cc(~)l ~_C}J s~~~L~x-=- In I sc ... e y + cosx = 0 with the initial condition y(O) = 1. -'f I. (. '/ +-(OS ... ,0); Concave down: (0,. 𝜋. 2. ) 7. 7. a. (0,−√7),(0,√7); b. dy. dx. = −2 ... ∫ln(cosx)tan(x)dx d. ∫. 1. √9−x2 dx e. ∫xcos(x)dx. 3 ... cosx = 0. So a = 0 and b = -1. 2 . The general solution is y = e. −x. (C1cosx ... sin2x +. 4. 5 cosx +. 3. 5 sinx . (c)(4pts) Try y = ax2e2x. Plugging in, we ...