Mở rộng bài toán giải phương trình sin(nx) + cos(x) = 0.

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cos(-x) = cos(x) sin(-x) = -sin(x) tan(-x) = -tan(x). Double angle formulas sin(2x) = 2 sinxcosx cos(2x) = (cosx). 2 - (sinx)2 cos(2x) = 2(cosx). 2 - 1 cos(2x)= ... Oct 27, 2024 ... Explanation: To solve the equation sin4x+sin2x=cosx in the interval 0∘≤x≤360∘, we can use trigonometric identities and algebraic manipulation. Find sin 2x, cos 2x, and tan 2x from the given information. Sin 2 x = 2 (~ 3/4 ) ( 1 /<) = -24/25. 86. cosx = CSC X < 0 ... Sin2x = 2(1/4)(-√√3/4). 2. Cos2x ... ... 0)}) = (1,0). – q({(cosx,sinx)}) = q({(cosx + 2,sinx)}) = (cos 2x,sin 2x) if 0 < x<π. – q({(cosx,sinx)}) = q({(cosx + 2,sinx)}) = (2 − cos 2x,sin 2x) if π 4. (e) f(x) = (. 2x + ... Suppose cosx < 0 and sinx = 4/5. cotx = 6. Suppose 1 + ln(x + 1) ... b) fanx cosx – COS X = 0. (osx (tanx-1)=0 cosx=o tanx = 1 tanxel. КП. I. X ... b) sin(2x) - sinx = 0. 25,0XCOSX. SINXEO. (210sx-1). SINX. SINYO. = COSXe. П п. X=0 ... a) sin 2x + cos x = 0 asin x cos x + COST = cosx (asinx+1)=0. = L cos X=0 sinx = -|. X=90,270°. Q3/4 x=90% - 90⋅. 2 b) sin 2x - cos 2x = 0 sinax = losax.
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