Xét phương trình $\sin^2(x + \epsilon) = \frac{1}{2}$ với $\epsilon$ là một số nhỏ. Tìm nghiệm gần đúng.

... 1, 2, 3 ; thus, of three terms only one will be written, the remaining ... sin c~ sin (133-132) [sin 3~fr+sin (~p_2/3,)] In like manner we shall have ... 2e2x - sinx. 1. = 2e0 - sin 1 = 2. Since lim x→0. (e2x - cosx) = e0 - cos 0 ... (a) limx→0(1 + 2x)1/x. Solution. Since (1 + 2x)1/x = e. 1 x loge(1+2x) ... Suppose we wish to solve sin 2x = √3. 2for 0 ≤ x ≤ 360◦. Note that in ... -1/2. 2. 6. 7. 6. 11. 1/2. 6 π π. - π π π π π π. -. Figure 14. Graphs of the ... Page 13. INTEGRAL #4. ∫ x + 1. (x2 + 2x + 2012)9. = 1. 2. ∫ du u9. [ u = x. 2. + 2x + 2012, dx = 2(x + 1)dx. ] = 1. 2. (. −. 1. 8u8. ) + C. = −. 1. 16(x2 + 2x + ... (c) 3 log(2x − 1) = 2. (d) 2e2x−1 = e5x. 19. Write the amplitude, period ... (b) y = 2 sin(2x+π). (c) y = −2 cos( x. 2 − π. 2. ) (d) y = −2 tan(4x−3) ... For f(x) = x + sin (2x) over [−. 𝜋. 2. ,. 𝜋. 2. ], find: a. Where f(x) is increasing and decreasing. b. The local minimums and maximums. c. The intervals ... x=(n−21​)π or (2n−1)2π​ Explanation: sin2x−1= ... = -. 1. 2 sin 2x - sin3 2x. 3 . And finally we use another trigonometric identity, cos2 x = (1 + cos(2x))/2: Z 3 cos2 2x dx = ... (x − 1)2. ≡. A. (x − 1). +. B. (x − 1)2 . Then. 2x + 2 ≡ A(x − 1) + B,. (3) ... sin 2x π. 4. 0. = 1. 4. [sin 2x] π. 4. 0. = 1. 4 sin π. 2. − sin 0. = 1. 4. − 0. =. 1. 2. -. 1. 2. (x - 1) = 1 -. 1. 2 x. 3). /. 3 sin(2x) dx =1. /. 3. 2 sin(t) dt = -. 3. 2 cost + C = -. 3. 2 cos 2x + C. / π. 2. 0. 3 sin(2x) dx = [-. 3. 2 cos ...