Trong mạch điện xoay chiều RLC, hệ số công suất cosφ có thể bằng -1/2 trong trường hợp nào?

Here cos x = - 12. Now sin2x+cos2 x =1. ⇒sin2x+(−12)2=1. ⇒sin2x=1−14. ⇒sin2x=34. ⇒sinx=±√32. But x lies in third quadrant. ∴ sin x =- √32. Now cosec x = 1sinx= ... ... cos (x) + V¹• cos(x) - J. Sin (x). Let us require. Then. Thus: u'.sin(x) + U ... =-λ(2-1) (2-2). Eigenvalues λ=1, 7=2, λ=1. 2=0: eigenvector [:] (comptation). Jun 5, 2019 ... COS X. -. 2x. -. 1. 2. = has only one real root, giving a reason for your answer. Given that the root of the equation is a, and that a is small,. x 1=2. D. 2 x. 2px ) h0.4/ D. 2 4. 2 2. D. 1. 64 h00.x/ D. 1. 2 "p x 2 x.1/ ln2 2 x 1. 2 x 1 ... k0.x/ D .sin x/.cos x/ C .cosx/. sin x/. D 2 sinx cosx. (c) Use ... May 11, 2022 ... -> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. -> Candidates must go ... Jan 11, 2024 ... Use the given information to cos(x - y).cos x = 2/9, sin y = -1/2, x in quadrant IV, y in quadrant III. Now Z x2 sin x dx = -x2 cos x + Z 2x cos x dx. This is better than the original ... 1)2 + b(xi+1) + c f(xi+2) = a(xi+1 + ∆x)2 + b(xi+1 + ∆x) + c. Not ... 2k cos x. Further, from Eq. (2),. Cos x = 2[((1 + /)2 - a2)1/2 + ((1 - f)2 - a2)1/2];. (Cos = '[((1 + a)2 _ #2)1/2 + ((1 a)2 _ -2)1/2] sin x cos y = a; cos x ... Jan 2, 2025 ... From the equation cos(X+Y)=0, we know that X+Y=90∘+n⋅180∘ for any integer n. Since X and Y are acute angles, we can take n=0, so X+Y=90∘. ... cos (x) + V¹• cos(x) - J. Sin (x). Let us require. Then. Thus: u'.sin(x) + U ... =-λ(2-1) (2-2). Eigenvalues λ=1, 7=2, λ=1. 2=0: eigenvector [:] (comptation).