Đề xuất các bài tập tự luyện về phương trình lượng giác có độ khó khác nhau.

ƒ' (1) = (2x + 2)|x=1 = 4. 54. ƒ (x) = (2x)4 − (2x)² + 1 = 16x4 − 4x² ... x)] = -4 sin x cos x = -2 sin 2x. = 26. h' (t). = d dt. [(12 d h" (t) = +2. = d. (a) 3 cos 2x + C. (b) 6 cos 2x + C. (c) 3. 2 sin2 2x + C. (d) 3. 2 cos 2x + C. (e) ... (x)=5x4 − 2 and f(1) = 4. Find f(−1). (a) 0. (b) 1. (c) 2. (d) 3. (e) 6 ... 1+ (x)² - 2 (∞) cos 2x f. +16-. 2. 1+ ($)² - 2 (3) cos 2x f. 10.16. -. 7.12 a) E ... 27 ['" (1 - 4)² αx. 2T. (. T αλ. 2T2. 3. 10.27. No/2. 721 a) Syx(ƒ) = H(f)Sx( ... Detailed step by step solution for cos^2(x)= 1/4. In С[-л,л], find the dimension of the subspace spanned by the vectors 1, cos(2x), and cos² (x). Justify your answer. Comparing w/ problem by cos² (x) = { + cos( ... −1 4 ,. 1. 2. −1 4 i. = p(1)(1) + (2)(2) + (−1)(−1) + (4)(4) = √22. In ... sin2 x dx. Now, using the identity sin2 x = 1. 2(1 − cos 2x) we get. Z π. −π. cos(x y) = cos x cosy sin x sin y. tan(x y) = (tan x tan y) / (1 tan x tan y). sin(2x) = 2 sin x cos x ... 1/4, 2/4, 3/4, 4/4. cos^2(a), 4/4, 3/4, 2/4, 1/4, 0/4. cos (2x+x) = cos 2x cosx - sin lysinx. = (2ccs ²x-1) cosx - 2 sin²x corx. = 2 ... N2 6 10 9 A 0 1 4 2. 4. Leave blank. Page 17. Question 6 continued. () sin ... Jun 2, 2024 ... My professor has us check our solutions to integrals by deriving the answer back to the initial problem. Given ∫cos4(x) = 1/4 (3/2 x + ... not occur because cos x + sin x = √2 cos(x − π/4) by trigonometry, and √2 ... and dividing 1/4 by 1/2 we have our answer, 1/2. 6.