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Jul 8, 2020 ... Jamia 2013: The value of the expression ( sin 3x/1+ cos x)+( cos 3x/1- sin x) is/are (A) √2 cos ( (π /4)-x ) (B) √2 cos ( (π /4)+x ) (C) √2 ... Differentiate wrt x \sin(x)\left(121\left(\sin(x)\right)^{2}\left(\cos(x)\right)^{4}-75\left(\cos(x)\right)^{2}\left(\sin(x)\right)^{ Oct 27, 2015 ... Prove the trig identity: cos 3a = 4cos^3 x - 3cos x Apply the trig identity: cos (a + b) = cos a.cos b - sin.a.sin b. cos 3x = cos (2x + x) ... Let x = cos 200. Then we get, from the formula for cos 3x,. 4x3-3x=4 cos3 20?-3 cos 200 =cos 3(200)= . .. 8x3=6x+1. We now have cos 200 cos 400 cos 800. =x(2x2 ... If x is an acute angle and sin ( x + 28 ° ) = cos ( 3 x − 78 ° ) then the angle is · The equation b cos ⁡ x 2 cos 2 x − 1 = b + sin ⁡ x cos 2 ⁡ x − 3 sin ⁡ x ... ∫ cos (3x + 5) dx. Solution: Let u = 3x + 5, then du/dx = 3 and dx = du/3 ... −1/3 cos (3x − 1) + C. Note: The final result can also be obtained using ... sen3(x - a) cos 3a + cos 3(x - a)sen3a - sen3a. x-a. =cos 3asen3(x - a) x-a+ ... x(cos 3x + 1) =0. Es decir, lim. '→a senx - sena. x-a =3 cos 3a. b ... Feb 8, 2023 ... d=−x1​x2​x3​. It is given that b=−9 and c=45 for parts (b) and (c) below. 2. 1. In the case that the three roots x1​,x2​ and x3​ form an ... period y=sin(x)*cos(3x). Natural Language; Math Input. Have a question about using Wolfram|Alpha?Contact Pro Premium Expert Support ». M(x) = e2x cos 3x sin 3x. - sin 3x cos 3x. & Y = M(x)C = e2x c1 cos 3x. - sin 3x. + c2 sin 3x cos 3x. (b) Find the solution of the initial value problem. M(0)C ...