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Nov 2, 2014 ... [tex]cos \alpha +cos \beta =2\cdot cos \frac{ \alpha + \beta }{2} \cdot cos \frac{ \alpha - \beta }{2}\\-----------------\\\\ \alpha =3x\ ... Apr 22, 2022 ... By clicking “Sign up”, you agree to our terms of service and acknowledge you have read our privacy policy. Sign up with Google. OR. Email. Yp = -9 A Cos 3x-9B Sin 3x. Plug into ODE: (-9A (os 3x-98 Sin 3x)+4(-3A Sin 3x + 3B Cos3x). + 4 CA Cos 3x + B Sin 3x). = [-5A ]. T-5. +12B Cos 3x + -12A-5B ... ∫ cos (3x + 5) dx. Solution: Let u = 3x + 5, then du/dx = 3 and dx = du/3 ... −1/3 cos (3x − 1) + C. Note: The final result can also be obtained using ... The solution to the differential equation can be determined by multiplying both sides of the equation by an integrating factor. Expression 1: "f" left parenthesis, "x" , right parenthesis equals cosine left parenthesis, 6 "x" , right parenthesis Has graph. To audio trace, press ALT+T ... Jul 1, 2019 ... Proof Tan 3x is = Sin 3x/ Cos 3x using De Moivre's theorem · updatesvc · Steven G · Dr.Peterson · updatesvc · Steven G · updatesvc. New member. ... by substitution: (a). Z x3 p x2 +2dx. (b*). Z x2 cos (x3)dx. (c). Z 1 x2 sin. 1 x dx. (d). Z cos(3x − 7) dx. (e). Z e√ x. √ x dx. (f*). Z e(x+ex) dx (use u = ex). Nov 10, 2016 ... Attempting to solve the 3rd derivative of cos(3x 2 ) and onward is simply infeasible due to it requiring multiplication rule and stuff. Nov 21, 2023 ... ... e − 2 x cos ⁡ 3 x {\displaystyle \displaystyle -6M{{e}^{-2x}}\sin 3x+(-8M+6N){{e}^{-2x}}\cos 3x-10Mx{{e}^{-2x}}\cos 3x=2{{e}^{-2x}}\cos 3x}.