lim ((n^2 + n) / (2n^2 - 1))?

Nov 21, 2017 ... See below. Explanation: I am assuming this is a limit to infinity, if not then this is completely wrong. limn→∞(1n2n−1). Nov 24, 2016 ... If n is pos. integer, then lim[n->infty](1/n)[(1/n)^2+(2/n)^2+...+((n-1)/n)^2]. Problem: Let Dn be the region below the hyperbola y = 1/x for 1 ≤ x ≤ n and above the union of the rectangles with base k ≤ x ≤ k + 1 and height 2/(2k + 3) ... Feb 7, 2024 ... Hi everyone Here's my progress so far, and I'm having trouble showing that `lim(a_n) >= lim(s_n)`: part 1 part 2 in those two screenshots ... Feb 2, 2012 ... is a Riemann sum for the integral 12∫10log1tdt=12. Added Feb.3 I said it was off-the-wall. The asymptotic expansion is from Maple, ... To solve the problem, we need to evaluate the two statements (S1) and (S2) and determine their limits. The limit comparison test applies with c = 1/2. The p-series P 1/n2 converges because p = 2 > 1. Therefore. P(1 − cos(1/n)) also ... Nov 24, 2016 ... +(nn−1​)2] can be expressed as... 3. See answers. AI Chat. Oct 14, 2008 ... f1(k) and c2 = lim k→∞ min{f1(k),f2(k)} exist. The proof of this ... (1))k)B(n/ log n)1/2. < exp(−B(n/ log n)1/2e−(c2+o(1))k). ≤ exp ... HINT: If we take logarithm of this expression we obtain n1​(ln(1+2/n)+ln(1+4/n)+…ln(1+(2n)/n)).