Đánh giá sai số của nghiệm gần đúng tìm được.

Page 2. INTEGRAL #1. READY,. GET SET,… 2:00. 2 0 1 4. U of S. I N T E G R A T I O N. B E E. U of S. I N. Page 3. INTEGRAL #1. ∫ π/2. 0. (2sinx + 3cosx) dx. 2 0 ... cos^2 x – (1-cos^2 x) +3cosx = -2. cos^2 x – 1+cos^2 x+3cosx +2 = 0. 2cos^2 x + 3cosx +1=0. Dla ułatwienia zamiast cosx podstawimy t, t∈<-1, 1>. 2t^2 + 3t+1=0. а) Решите уравнение cos2x-3cosx+2 = 0. б) Найдите все корни уравнения, принадлежащие отрезку . Решение. а) Преобразуем выражение, получим: Сделаем замену и ... 2 cos2 θ - 1 = cos 2θ. cos 0∘ = cos 2π = 1 and cos (π/3) = 1/2. Calculation: Given that,. cos 2x - 3 cos x = - 2. ⇒ 2 cos2 x - 1 - 3 cos x + 2 = 0 (∵ 2 cos2 θ - ... Feb 4, 2016 ... Himpunan penyelesaian dari persamaan cos 2x – 3 cos x + 2 = 0, 0˚ ≤ x ≤ 360˚ adalah … (Ujian Nasional Matematika Tahun 2011) **Super Intensif UN ... Z sin2 x cos2 x dx = Z. 1 - cos(2x). 2. ·. 1 + cos(2x). 2 dx. The remainder is left as an exercise. Exercises 8.2. Find the antiderivatives. 1. Z ... = 4cos3 x − 3 cosx. 5. Page 6. (b) Deduce that (not unexpectedly) sin π. 6 ... cos(x/2) > 0). Rearranging, we get sin2(x/2) = t2. 1 + t2 or sin(arctant) ... 2 cos2 x + 3 cos x + 1 = 0 ... cos x = sin^2 (x/2). Solve the given trigonometric equation for x in the interval 0 leq x leq 2pi. 2 cos2 x + 5 cos x + 2 = 0 ... Feb 17, 2012 ... Let y=cos(x). Then the equation becomes 3y2+y−2=0. This can be solved using the quadratic formula or any other method for solving quadratics ... Jan 12, 2020 ... 7-3cosx=9(cos^2x-cos2x) 7-3cosx=9(cos^2x-(2cos^2x-1)) 7-3cosx=-9cos^2x+9 9cos^2x-3cosx-2=o let y=cosx 9y^2-3y-2=0 (3y-2)(3y+1) cosx=2/3