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), the zeros of 2cosx + 3x2sinx are zeros of ctgx+^x2. ctgx + jx2 has zeros xme(mn,(m+ 1)TT)(WJ= ± 1, +2,...). Hence k. (2 cos x + 3x2 sin x) = 1. Therefore ... Detailed step by step solution for integral of (-2cos(x)) When the polynomial 3x^3 +ax+ b is divided by x−2 , the remainder is 2, and when divided by x +1 , it is 5. Find the value of a and the value of b. ... Answered ... Feb 20, 2024 ... Let Sn(x)=∑nk=0Pk(x), and Un(y)=Sn(2−2y), it is easy to prove that U0(y)=1, U1(y)=1+1−(2−2y)=2y and Un+1(y)=2yUn(y)−Un−1(y). Jan 31, 2024 ... Questions Asked in JEE Main exam. If α + i β \alpha + i\beta α+iβ and γ + i δ \gamma + i\delta γ+iδ are the roots of the equation x 2 − ( 3 − 2 ... Dec 16, 2024 ... The least value of the function f(x) = 2 cos x + x in the closed interval [0, π/2] is: (a) 2 (b) π/2 + √3 (c) π/2 (d) The least value does not Sep 16, 2021 ... Explanation · Show that 2cos xcot x+1=cot x+2cos x can be written in the form acos x-bcos x-sin x=0 , where a and b are constants to be found. Nov 4, 2024 ... (2 cosx-1) Cos × 70. <). 2 cosx-170. X. ^ cosx to. ↓ x = = = ^ x x ... 2COSX-1 >O cosx 7. 2. - π. 3. < x <. 3. ~TC < x <. У. 0 < x < 1/5. 3. S₂ = ... Jun 12, 2023 ... Now, we'll need f'(x) since [f-1(x1)]' = 1/[f'(x2)] where f(x2) = x1. f'(x) = 3x2 + 3cosx - 2sinx, then f'(0) = 3. Plugging this into the above ... ... (2cosx) = sinnx sinx . (b) Montrer que pour tout n ≥ 1, Vn est unitaire de degré n−1. (c) Montrer que. Vn(t) = n−1. ∏ k=1. (t −2cos kπ n. ) 2. (a) Calculer ...